UIApplication
public extension UIApplication
-
返回
UIViewControllerRouter.sharedDeclaration
Swift
var router: UIViewControllerRouter { get } -
通过链接进行页面跳转
Declaration
Swift
@inline(__always) func route(url: URLComponentsConvertible, object: Any? = nil) -> RouteRequestParameters
url路由链接
object业务对象,默认为nil
Return Value
返回一个
RouteRequest实例 -
直接进行页面跳转
Declaration
Swift
func route(viewcontroller: UIViewController) -> RouteRequestParameters
viewcontroller想要跳转的
UIViewController实例Return Value
返回一个
RouteRequest实例
UIApplication Extension Reference