UIApplication
public extension UIApplication
-
返回
UIViewControllerRouter.shared
Declaration
Swift
var router: UIViewControllerRouter { get }
-
通过链接进行页面跳转
Declaration
Swift
@inline(__always) func route(url: URLComponentsConvertible, object: Any? = nil) -> RouteRequest
Parameters
url
路由链接
object
业务对象,默认为nil
Return Value
返回一个
RouteRequest
实例 -
直接进行页面跳转
Declaration
Swift
func route(viewcontroller: UIViewController) -> RouteRequest
Parameters
viewcontroller
想要跳转的
UIViewController
实例Return Value
返回一个
RouteRequest
实例